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@Python_Dv 1*(4+1)=5 2*(5+1)=12 3*(6+1)=21 5*(8+1)=45

@Python_Dv (0+0) + 0 = 0 (1+4) + 0 = 5 (2+5) + 5 = 12 (3+6) + 12 = 21 (5+8) + 21 = 34 Final answer = 34

@Python_Dv 45 Easy: 1 + 4 = 5 [ 1 + (1 * 4) = 5 ] 2 + 5 = 12 [2 + (2 * 5) = 12 ] 3 + 6 = 21 [3 + (3 * 6) = 21 ] 5 + 8 = 5 + (5 * 8) = 45

@Python_Dv 1+4 = 5 2+5 = 12 ... (which is 5 + (2+5)) 3+6 = 21 ... (which is 12 + (3+6)) 5+8 = 34 ( which is 21 + (5+8))

@Python_Dv I got this rule: a+b=a×b+a(in real math) Base Case Verification: 1 + 4 = 1×4 + 1 = 5 , 2 + 5 = 2×5+2=12, 3+6=3×6+3=21,all hold. Inductive Step: Assume k+(k+3)=k×(k+3)+k holds. It can be deduced that (k+1) + (k+4) = (k+1)×(k+4) + (k+1) also holds. Thus, 5+8=5×8 + 5 = 45

@Python_Dv 1*4+1= 5 2*5+2= 12 3*6 +3= 21 5*8 +5= 45

@Python_Dv 45

@Python_Dv 45:- 5*8+5

@Python_Dv True, false, false, 13

@Python_Dv 34

@Python_Dv 45 (5x8+5)

@Python_Dv 45

@Python_Dv 34

@Python_Dv 34

@Python_Dv 45

@Python_Dv 34

@Python_Dv 45

@Python_Dv 45

@Python_Dv 45

@Python_Dv 1+(4*1)=5 2+(5*2)=12 3+(6*3)=21 5+(8*5)=45

@Python_Dv 34

@Python_Dv 45

@Python_Dv 45

@Python_Dv 45

@Python_Dv 45

@Python_Dv 34

@Python_Dv 5+8 = 13 don't assume a hidden pattern when there is no evidence of it. it does not ask: x + (1+4) =5 It doesn't ask for a row estimate. it only asks what 5+8 is, nothing more, nothing less.

@Python_Dv 45

@Python_Dv 8 x 5 = 40 + 5 = 45 The 2nd number s multiplied by the 1st number, and then we add the 1st number to the result.

@Python_Dv 45

@Python_Dv 45

@Python_Dv 34

@Python_Dv 34

@Python_Dv 34

@Python_Dv 45

@Python_Dv 32+5+8=45