What is the output of this code, and why?🤔 #python

@PythonPr [1] Don't oversee the "break".

@PythonPr [1]. After first iteration of if inside the for loop, there comes break statement, therefore, one iteration is completed printing [1]

@PythonPr 2,4

@PythonPr B. [1]

@PythonPr The output is B. [1] because the loop skips even numbers using continue and adds the first odd number (1) to the list before stopping with break. Can you see how break affects the loop's flow? It’s a neat way to control which elements get processed!"

@PythonPr b. [1]

@PythonPr [2,4]

@PythonPr The loop ends after processing only the first number (1) Correct answer is b. [1]

@PythonPr [1] , 1 % 2 == 0 is False (1 is odd): 1 is appended to some_numbers Then break is executed, which exits the loop immediately

@PythonPr A

@PythonPr b

@PythonPr [1]

@PythonPr [1]

@PythonPr D

@PythonPr D - the condition states if the number is divisible by 2 with no reminder, then append the number to the new list some_numbers.

@PythonPr C

@PythonPr B

@PythonPr Should be Option B

@PythonPr b

@PythonPr b

@PythonPr B.

@PythonPr b