Python Quiz : What is the Output?

@PythonPr It's D a is an integer and b is a string in this code So 9 is seen like an alphabet that should be written 4 times

@PythonPr C

@PythonPr Personally, I think it's C. Error. Because a is a string and b is numerical.

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@PythonPr D

@PythonPr The answer is D but I don't know why😭

@PythonPr Error because you can't add string and numeric value together

@PythonPr Que imprima el 9; cuatro veces ,9999

@PythonPr D

@PythonPr 9999

@PythonPr D

@PythonPr c

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@PythonPr D

@PythonPr D

@PythonPr 9999

@PythonPr 36

@PythonPr 9999

@PythonPr C

@PythonPr It's interesting that these are potential genericizations and overloadings of the arithmetic symbols . In current development CoSy , need to be more specific : ` 9 4 _take 9999 as a string .

@PythonPr Error, because the variable a being a character string cannot be multiplied to an integer. So the exit is C

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@PythonPr D

@PythonPr 9999

@PythonPr 9999

@PythonPr youtube.com/shorts/LIgVel9…

@PythonPr Error..bcz a is a string

@PythonPr D

@PythonPr D

@PythonPr 9999

@PythonPr c

@PythonPr Error you can't add numbers and strings

@PythonPr D 9999

@PythonPr Answer: D Solution: The python does different things for different kinds of operators. a is a string, '9'. b is an int, 4. In python, string-int multiplication is defined as repepetition of the string, int number of times. So, '9' * 4 gives 4 repetetions of 9, ie, "9999".

@PythonPr D

@PythonPr D

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@PythonPr Error!

@PythonPr D

@PythonPr D