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Option C : [1, 2, 3] [1, 2, 3, 4] Explanation👇 a = [1,2,3] creates a list. b = a[:] creates a copy of list `a` using slicing. Now `b` is a **separate list in memory. b.append(4) adds `4` only to `b`, not to `a`. Since `a` and `b` are different lists, modifying `b` does not affect `a`. Key point: `a[:]` makes a **shallow copy**, not a reference.

@Python_Dv Answer: (C) This problem tests the understanding of list copying in Python. Variable Assignment: The line a = [1, 2, 3] creates a list and assigns it to variable a. Slicing for Copy: The expression a[:] creates a shallow copy of the list a and assigns it to b. This

@Python_Dv C

@Python_Dv c

@Python_Dv It is c because a is not appended it was b that was appended.

@Python_Dv Answer: C. Slice [:] copies the list → a stays [1,2,3], b becomes [1,2,3,4].

@Python_Dv output: 👉 [1, 2, 3] [1, 2, 3, 4] Reason? a[:] creates a shallow copy of the list. So b is a new list. Appending to b doesn’t affect a. b = a Then both would change. 😄 Copy vs reference. Classic Python interview trap.

C. [1, 2, 3] [1, 2, 3, 4]. Two concepts are in play here. The first is the concept of slicing and the second one is the append method. b = a[ : ]. This means slice through "a" from the beginning to the end. Which gives [1, 2, 3]. b.append(4). Means add 4 to the existing values of b, but as the last element. This gives [1, 2, 3, 4]. So print(a, b) gives the answer.

@Python_Dv 1. b = a[:] this type of assignment is an old fashioned way of copying. This means variable b is an separate memory from variable a. Changes made to variable b won't affect variable a 2. Output will be [1,2,3][1,2,3,4]

@Python_Dv C

@Python_Dv C

@Python_Dv C. We have two lists in differtmemory locations. Only b is modified in place. So the result is[1,2,3] [1,2,3,4]

@Python_Dv C

@Python_Dv C

@Python_Dv Option C

@Python_Dv C) is the right answer.

@Python_Dv C

@Python_Dv C

@Python_Dv Error

@Python_Dv And= C. appending affect only( b) not (a)

@Python_Dv b = a[:] creates a 'shallow copy' of a. Now a and b share different memory and .append() outputs option 'C'. [:] is a slicing technique which copies everything from start to end. Unlike append(), slicing creates a brand new list without altering original list.

@Python_Dv C

@Python_Dv C

@Python_Dv C

@Python_Dv C

@Python_Dv B