Python Question / Quiz; What is the output of the following Python code, and why? Comment your answers below!

@PythonPr Answer: C) Error The trap: Both are STRINGS! › a = '9' (string, not number) › b = '4' (string, not number) › String * String = TypeError! For beginners: String * int works ('9'*4='9999'), but string * string doesn't.

@PythonPr The correct answer is C) Error. Why is it an error? In Python, the * operator is overloaded, meaning it does different things depending on the data types: Number * Number: Standard multiplication (e.g., 9 * 4 = 36). String * Integer: String repetition (e.g., '9' * 4 = '9999').

@PythonPr C) Error '9' * '4' = TypeError String * String = Python says no. String * Int = Python says "9999" (if it was '9' * 4) The trick: multiplication needs at least one integer.

@PythonPr C Because we can't multiply strings but we can add them

@PythonPr C) Error Because a and b are both strings. In Python, string multiplication only works with an integer, not another string ('g' * 4 works, 'g' * '4' does not).

@PythonPr Output: C) Error Why: In Python, string multiplication works only with an integer (e.g., 'g' * 4). Here, b = '4' is a string, so a * b raises a TypeError (can't multiply sequence by non-int).

@PythonPr a and b are string... when you write '9" * '4', python sees: left and right side sequence (string). It expects the right side to be an int. since it is noy, python riases error

@PythonPr This is an error. ‘a’ and ´b’ are strings. We cannot multiply strings

Answer: D) 9999 In Python, multiplying a string by an integer (in this case, the string '9' by the string '4', which Python implicitly converts to the integer 4 for this operation) results in the string being repeated that number of times. Therefore, '9' multiplied by 4 equals '9999'

@PythonPr C) Error

@PythonPr C

@PythonPr 36

@PythonPr error bcoz string string cant be multiplied 😁 TypeError: cant multiply sequence by non-int of type str

@PythonPr a is a string b is also a string Python does not allow multiplying a string by another string string * int → string repetition string * string → TypeError so output=TypeError

@PythonPr d

@PythonPr 9999

@PythonPr C

@PythonPr I hit the same wall with debugging code in the past. Most times it's not about solving the issue itself but understanding what the variable holds at each step. It's crazy how a single print statement can save you from hours of head-scratching.

@PythonPr C

@PythonPr '94'

@PythonPr C

@PythonPr B

@PythonPr Error i guess

@PythonPr C) TypeError, we can't multiply strings

@PythonPr A

@PythonPr A

@PythonPr C. Error. You cannot multiply strings

@PythonPr Error

@PythonPr A

@PythonPr A

@PythonPr error

@PythonPr I would go for C

@PythonPr C) Error '9' and '4' are of type (string) and python needs at least one integer(e.g 4) for multiplication to work.

@PythonPr Error cos of type is string and not int