Brain Booster

b² = ???

@IQTestBrain p × q = 24 p - q = 2 p = 6 , q = 4 p + q = 6 + 4 = 10 ✅

P+q = ?

@IQTestBrain K + K / K = 6 2K / K = 6 2 K = 6K 6 K - 2K = 0 4 K = 0 K = 0 But, K≠ 0 Correct answer = Not defined ✅

Find k

@MathGuyTFL a + a = 12 a = 6 a + a × a = 6 + 6 × 6 = 6 + 36 = 42 ✅

Find: a + a × a = ?

@MathGuyTFL 2 ( x + 9 ) = 26 x + 9 = 13 x = 4 ✅

Find the value of X.

∠AOB = ???

@LucreciaPrf3 You have solved the question very well.🥰

@BrainBoosterX (2;-3)

Try this. P = ???

@MathGuyTFL B + B + B = 21 B = 7 C = 5 C × C + A = 5 × 5 + 7 = 25 + 7 = 32 ✅

C × C + A = ?

@IQTestBrain x + y = 27 x - y = 3 √ x² - y² = √ 27 × 3 = √ 81 = 9 ✅

√x²-y² = ?

@slimsesan Nice explanation ✅👌 👍

Step-by-Step Solution: We know that the tangent is perpendicular to the radius at the point of contact. Therefore: OA ⊥ PA ⇒ ∠OAP = 90° OB ⊥ PB ⇒ ∠OBP = 90° Consider the quadrilateral OAPB. The sum of interior angles in any quadrilateral is 360°. In quadrilateral OAPB: ∠OAP = 90° ∠OBP = 90° ∠APB = 30° (given) Let ∠AOB = θ (this is the angle we need to find) Therefore: 90° + 90° + 30° + θ = 360° 210° + θ = 360° θ = 360° − 210° θ = 150° Hence, ∠AOB = 150°

@slimsesan ❤️

@BrainBoosterX Nice to know you liked it.

Friction always acts ???

@slimsesan Nice 💯

@BrainBoosterX Opposite to motion.

@kzd6IBjvsf0q319 Very good 👍

@BrainBoosterX ( t × t ) / t = 0 t ² / t = 0 t = ０ ( t ≠ 0 ) However,there is a ”division by zero rule”which states that the denominator cannot be zero, so this equation has no solution.

Comment your answer. t = ???

@johnjohn2470 @MathGuyTFL 🥰❤️

@BrainBoosterX @MathGuyTFL Thank you the opportunity to learn from you ✅👍🏻

Find the value of X.

@IQTestBrain P / 10 = 4 /5 P = 4 × 10 / 5 P = 8 ✅

Find p

@IQTestBrain a² = 49 a = 7 , - 7 a b = 70 b = 10 , -10 b² = 10² , (-10)² b² = 100 , 100 b² = 100 ✅ Correct answer

b² = ❓

@H0H0v Oscillate for a longer duration = B ✅

Which one will oscillate for a longer duration?

@lovebluek01 Nice 👌

@BrainBoosterX => p^2 + p - 6 = 0 => p^2 + 3p - 2p - 6 = 0 => p(p + 3) - 2(p + 3) = 0 => (p + 3)(p - 2) = 0 ■ p + 3 = 0 => p = -3 ■ p - 2 = 0 => p = 2