Deepak Goyal

Hi, I'm Deepak and I share daily knowledge about: 💻 Azure Cloud Solution 🏆 Microsoft Azure technologies 📦 Technical Blogs ⚡ Productivity tips 💼 Career development 🎉 Azure certifications 🚀 Technical queries and challenges If you want to learn, make sure to follow me! ✅

Starting 𝐅𝐫𝐞𝐞 𝐋𝐢𝐯𝐞 𝐏𝐲𝐭𝐡𝐨𝐧 𝐂𝐨𝐮𝐫𝐬𝐞 which will teach u: 1. Logic Building 2. Remove programming 𝐏𝐡𝐨𝐛𝐢𝐚 3. 𝐌𝐚𝐬𝐭𝐞𝐫 𝐏𝐲𝐭𝐡𝐨𝐧: 𝐋𝐚𝐬𝐭 𝐟𝐞𝐰 free 𝐬𝐞𝐚𝐭𝐬 𝐥𝐞𝐟𝐭. 𝐉𝐨𝐢𝐧 𝐭𝐡𝐞 𝐜𝐨𝐡𝐨𝐫𝐭 𝐟𝐨𝐫 $𝟎 𝐡𝐞𝐫𝐞: 👇 academy.azurelib.com/checkout/Cours…

Stop learning python for sure if you are trying hard but always find difficult how to build logic Then this is for you,

@acharyaveda_ Radhe radhe

कल शाम तक कोई अच्छी खबर मिलेगी बस मन से एक बार ( राधा राधा ) लिख दो..

@GitaShlokas_ Jai maa laxmi

Do it🙌

@sabir_huss50540 All

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10. Find all employees whose names contain the letters "a" exactly twice SELECT * FROM employees WHERE LENGTH(name) - LENGTH(REPLACE(LOWER(name),'a','')) = 2 11. Running total of sales by date SELECT date, sales, SUM(sales) OVER (ORDER BY date) AS RunningTotal FROM sales_data

9. Get Employee Details with Department Names SELECT e.name, d.department_name FROM employees e JOIN departments d ON e.department_id = d.department_id

7. Get Total Salary by Department SELECT department, SUM(salary) AS total_salary FROM employees GROUP BY department 8. Find Nth Highest Salary (Nth = 3) SELECT DISTINCT salary FROM employees ORDER BY salary DESC LIMIT 1 OFFSET 2

5. Find Employees Who joined in 2024 SELECT * FROM employees WHERE YEAR(joining date) = 2024 6. Find Customers Without Orders SELECT c.customer_id, c.name FROM customers c LEFT JOIN orders o ON c.customer_id = o.customer_id WHERE o.customer_id IS NULL

5. Find Employees Who joined in 2024 SELECT * FROM employees WHERE YEAR(joining date) = 2024 6. Find Customers Without Orders SELECT c.customer_id, c.name FROM customers c LEFT JOIN orders o ON c.customer_id = o.customer_id WHERE o.customer_id IS NULL

4. How can you delete duplicate records WITH CTE AS ( SELECT column_name, ROW_NUMBER() OVER (PARTITION BY column_name ORDER BY column_name) AS row_num FROM table_name ) DELETE FROM CTE WHERE row_num > 1

3. Find Duplicate Records SELECT column_name, COUNT(*) FROM table_name GROUP BY column_name HAVING COUNT(*)>1

SQL INTERVIEW QUESTIONS SERIES : 1. Find the 2nd Highest Salary SELECT MAX(salary) FROM employees WHERE salary < (SELECT MAX(salary) FROM employees) 2. Count Of Employees in Each Department SELECT department, COUNT(*) AS employee_count FROM employees GROUP BY department

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How do you find the 2nd highest salary from an employees table? SELECT MAX(salary) FROM employees WHERE salary < (SELECT MAX(salary) FROM employees); 💡Explanation: This filters out the max salary, then finds the next highest. 🎯 Tip: Use DENSE_RANK() for general Nth salary.

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