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@PythonPr Answer: A. 1
The code iterates through a nested list to find the minimum value. Initially, x is set to the first element of the nested list, which is values[0][0] or (3). The outer loop iterates through each inner list ([3, 4, 5, 1] and [33, 6, 1, 2]). The inner
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@PythonPr First list [3, 4, 5, 1]
element = 3 -> x > element? -> 3 > 3 False
element = 4 → 3 > 4 False
element = 5 → 3 > 5 False
element = 1 → 3 > 1 True → x = 1
So Answer
x = 1
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@PythonPr A). the code scans every number in the nested lists and keeps updating x whenever it finds something smaller and the smallest value in all the lists is 1.
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@PythonPr CheatCode
1. list of lists (a 2D array or matrix).
2. values[0] accesses the first inner list, which is [3, 4, 5, 1].
3. [0]then accesses the first element within that inner list.
4. values[0][0] evaluates to 3.
5. 2nd (for loop) combs through values
6. 3 > 1 & 2
7. 1 smaller
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