Brain Booster

∠AOB = ???

Comment your answer. H = ???

@IQTestBrain A² + A² = 50 A² = 25 A = ±5 B² = 41 - 25 B² = 16 B = ±4 A - B = 5-4 or -5 - (-4) A - B = 1 or -1 ✅

A-B = ?

m + n = ???

@IQTestBrain a⁴ + a⁰ / a⁰ = 82 a⁴ + 1 / 1 = 82 a⁴ = 81 a = 3, -3 ✅

SOLVE

@MathGuyTFL x² -25 / x -5 = 10 x² -25 = 10x -50 x² -10x +25 = 0 (x - 5 )² = 0 x = 5 But, x ≠ 5 Final answer = No Solution ✅

Find the value of X.

@IQTestBrain 3N / √N = 12 √N = 4 N = 16 ✅

SOLVE:

@IQTestBrain 5√3 / √125 = √n 5√3 / 5 √5 = √n √3 / √5 = √n √3/5 = √n n = 3/5 2n = 6/5 ✅

Find 2n

@H0H0v 360 - 320 = 40 180 - 85 = 95 x = 40 + 95 = 135 ° ✅

x=?

@IQTestBrain 3^2x = 3⁴ 2x = 4 x = 2 ✅

X = ?

@H0H0v 1 / ( 1/H + 1/H + 1/H ) = 1 1 / ( 3 /H ) = 1 H /3 = 1 H = 3 ✅

H=?

@IQTestBrain p × q = 24 p - q = 2 p = 6 , q = 4 p + q = 6 + 4 = 10 ✅

P+q = ?

@IQTestBrain K + K / K = 6 2K / K = 6 2 K = 6K 6 K - 2K = 0 4 K = 0 K = 0 But, K≠ 0 Correct answer = Not defined ✅

Find k

@MathGuyTFL a + a = 12 a = 6 a + a × a = 6 + 6 × 6 = 6 + 36 = 42 ✅

Find: a + a × a = ?

@MathGuyTFL 2 ( x + 9 ) = 26 x + 9 = 13 x = 4 ✅

Find the value of X.

∠AOB = ???

@LucreciaPrf3 You have solved the question very well.🥰

@BrainBoosterX (2;-3)

Try this. P = ???

@MathGuyTFL B + B + B = 21 B = 7 C = 5 C × C + A = 5 × 5 + 7 = 25 + 7 = 32 ✅

C × C + A = ?

@IQTestBrain x + y = 27 x - y = 3 √ x² - y² = √ 27 × 3 = √ 81 = 9 ✅

√x²-y² = ?

@slimsesan Nice explanation ✅👌 👍

Step-by-Step Solution: We know that the tangent is perpendicular to the radius at the point of contact. Therefore: OA ⊥ PA ⇒ ∠OAP = 90° OB ⊥ PB ⇒ ∠OBP = 90° Consider the quadrilateral OAPB. The sum of interior angles in any quadrilateral is 360°. In quadrilateral OAPB: ∠OAP = 90° ∠OBP = 90° ∠APB = 30° (given) Let ∠AOB = θ (this is the angle we need to find) Therefore: 90° + 90° + 30° + θ = 360° 210° + θ = 360° θ = 360° − 210° θ = 150° Hence, ∠AOB = 150°