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@Python_Dv Answer A). 32.0
The variable x is initialized to 4.
The condition (x<10) (i.e., (4<10) is true. The loop body executes. The expression (x*=x/2) is equivalent to (x=x*(x/2)). (x=4*(4/2)=4*2=8) The value of (x\) is now 8.
The condition (x<10) (
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@Python_Dv Output: Option A - 32.0
x starts as 4. While x is less than 10, the loop runs. First pass: x becomes 4 * (4/2) = 8. Since 8 is still less than 10, it runs again: x becomes 8 * (8/2) = 32. Now x is not less than 10, so the loop stops and prints 32.0.
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@Python_Dv Es un error de sintaxis, pues el operador debe escribirse todo junto "*=".
Por tanto, la respuesta es la D.
Español
@Python_Dv explanation would be:
For the statement: x *= x/2
when x=4
x*=x/2 will be x=4/2*4 that is 8
when x=8
x*=x/2 will be x=8/2*8 that is 32
hence the answer is 32.
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@Python_Dv Output is 8.0 and 32.0
That loop prints two lines, not one.
If the intended operator is *= (i.e., x *= x/2), then:
Start x = 4
Iteration 1: x = 4 * (4/2) = 8.0 → prints 8.0
Iteration 2: x = 8 * (8/2) = 32.0 → prints 32.0
Stop (since 32.0 < 10 is false)
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@Python_Dv The answer is 32.0, because in the first iteration, x will be 8.0 (x = 4 * 4/2), then x will be 32.0 (x = 8 * 8/2) so the output will be 32.0
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@Python_Dv the answer would have been A:32, if x*=x/2
but the answer is
D:none of these. b/c of invalid syntax " "
x* = x/2.
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@Python_Dv Looks like python. Mine is complaining about the blank after the asterisk in line 6. SyntaxError: Invalid syntax
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@Python_Dv A: x starts at 4, x < 10, so enters loop. Assignment reduces to x *= (4/2) so x is now 8. Still < 10, goes through loop x *= (8/2) so x = 32, loop exits
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