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@PythonPr Answer: B (4)
For beginners: Python uses 0-based indexing!
› x[0] = 7 (first element)
› x[1] = 4 (second element)
› x[2] = 9 (third element)
Index 1 gives the SECOND element, not the first! This trips up many beginners coming from 1-based counting.
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Answer: B. 4
Why:
Python uses zero-based indexing → The first element is at position 0.
So:
x[0] = 7
x[1] = 4 ← This is what gets printed
x[2] = 9
Common confusion: New programmers often think x[1] means "first element" (like in math), but in programming, counting starts from 0.
Great question for beginners! What's the next concept they should learn?
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@PythonPr Answer: B 4
In Python, list indexing starts at 0. This means that each element in the list is assigned a position number starting from zero:
x[0] refers to the first element: 7
x[1] refers to the second element: 4
x[2] refers to the third element: 9
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@PythonPr The answer is B, because python and most other programming languages start indexing from 0
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@PythonPr Answer: B) 4
Python lists are 0-indexed.
So for x = [7, 4, 9]:
x[0] → 7
x[1] → 4
x[2] → 9
print(x[1]) outputs 4
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@PythonPr Option-B (4) because of In array index is start from 0 that's why print(x[1]) which is 1's postion which is 4 and 0 postion of index is 7 and also 9 which is postion of index 2.
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@PythonPr Python lists use zero-based indexing
Index positions are x[1]
so the output= 4
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@PythonPr B) 4 is right answer.
The basic concept of list indexing.
The indexing start from 0 to len(x)-1.
X[0]= 7
X[1]= 4
X[2] = 9
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@PythonPr The output is B)4
because of zero-based indexing: x[0]=7, x[1]=4, x[2]=9. Understanding this is crucial for effective list manipulation in Python."
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@PythonPr B , because in programming number starts from 0 not 1.
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