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@PythonPr Still there since the remove method only removes the first match. The last 2 is still there.
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@PythonPr The output will be "Still There." The remove method will remove the first occurrence of the element given it, in this case the value of 2. Since a second value of 2 is in the list, it will remain and the "Still There" will print.
The value x after the remove would be: [1, 3, 2]
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@PythonPr Your code will not compile because it has a drop shadow. This will prevent the compiler from reading the code.
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