Python Quiz: What is the output ?📷

@PythonPr [1,2] is the output since the copy() method caused b to be bound to a new object in memory. The append() did nothing to a.

@PythonPr a = [1, 2 ] It's a shallow copy. Both a and b are pointing to different reference.

@PythonPr [1,2] it's a shallow copy and they both are point to different reference.

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@PythonPr [1, 2]

@PythonPr Answer: [1, 2] b = a.copy() makes a shallow copy, i.e., a new list with contents 1 and 2. Thus, a and b point to separate lists in memory. Appending 3 to the list pointed to by b updates only that list. The list pointed to by a remains unchanged.

@PythonPr [1, 2]

@PythonPr 1,2. a never changed

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@PythonPr [1, 2]

@PythonPr [1,2] Shallow Copy:The command b = a.copy() creates a new list object b that contains the same elements as a. Since b is a separate copy, any modifications made to b (like b.append(3)) do not affect the original list a. When you print(a), it remains unchanged.

@PythonPr Output : [ 1 , 2 ] ... .@PythonPr

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@PythonPr [1, 2] ?

@PythonPr [1,2]