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@Python_Dv Answer: A) 1 Explanation The variable x is initialized to 5.The while loop condition x > 2 is checked:First iteration: (5>2) is true. x becomes (5-2=3).Second iteration: (3>2) is true. x becomes (3-2=1).Third iteration: (1>2) is false. The loop terminates.
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@Python_Dv Answer: A) 1
Explanation:
Start with x = 5.
Loop runs while x > 2.
5 → subtract 2 → 3
3 → subtract 2 → 1
1 is not greater than 2, so the loop stops
print(x) runs after the loop, so the output is 1.
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@Python_Dv Code had used the same variable (lowercase x throughout):
Start: x = 5
First Pass: 5 > 2 is true. x becomes 3.
Second Pass: 3 > 2 is true. x becomes 1.
Third Pass: 1 > 2 is false. Loop ends.
Final Print: It would print 1.
For More Reference =>>
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@Python_Dv A) 1.
While loop only breaks when the condition is false. 5 greater than 2 = True, loop continues, x -= 2 means subtract 2 from x if x is greater than 2, so x becomes 3. 3 greater than 2 is True, x -= 2, x becomes 1. 1 greater than 2 = False the loop breaks and prints 1.
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@Python_Dv Will just print 1, because 1<2 and in every cicle the variable decreases 2. The while doesn't run when x<2, and the print occurs after it.
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@Python_Dv 1
3>2
Evaluate too 3-2=1 since 5>2 likewise
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