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@Python_Dv D) A\nC x = 5, so x > 3 is True → prints "A" print("C") is outside the if/else block, so it runs regardless. The sneaky indentation trap strikes again.

@Python_Dv The output is an indentation error.... What did you just cook at print ("c") ?

@Python_Dv D is right answer A C Simple use of if and else condition Here if condition is true then output will A then else condition is false, but the last print("C") will work and print by default separator is change the line so out put will be A/nC

@Python_Dv x > 3 → True, so "A" is printed The else block is skipped print("C") is outside the if–else, so it always runs output A C

@Python_Dv the exercise is poorly formulated, the response on the console is A

@Python_Dv The answer is A C

@Python_Dv The output is: A Because x = 5 and 5 > 3 is True, Python enters the if block and prints "A". The else block is completely skipped, and since print("C") is inside the else block (same indentation as print("B")), it never runs.

@Python_Dv A)

@Python_Dv A) A C

@Python_Dv D

@Python_Dv A

@Python_Dv (A)

@Python_Dv Option A

@Python_Dv A