What is the output? Write your answer in the comments and share it with your friends✅✅

@Python_Dv The output is: 15 5 Why: Inside func(), value = 15 is a local variable, so print(value, end=" ") prints 15. Outside the function, the global value stays 5, so print(value) prints 5. Correct choice: A ✅

@Python_Dv Global vs. Local Scope The answer is A): 15 5. This tests your knowledge of variable scope—specifically, how Python distinguishes between variables defined inside a function and those defined outside of it. Why is the answer 15 5? Global Initialization: value = 5

@Python_Dv value inside func() is a local variable, and value outside is a global variable. What happens: •Inside func(), Python uses the local value = 15 •Outside, Python uses the global value = 5 Output: 15 5

@Python_Dv Answe is A (15,5), we have a global value 5 which is outside of the fxn(), and the fxn() uses the local value 15

@Python_Dv Answer: 15 5 — local value inside func() doesn’t change the global value.

@Python_Dv A

A ...good example of 'scope'

@Python_Dv A) 15 5

@Python_Dv 15 5

@Python_Dv Can someone explain / tell me what is the effect of end= “ “ ??

@Python_Dv A. 15 and 5 First, the function is called and then the value

@Python_Dv A

@Python_Dv ~ 15, 5

@Python_Dv 15 5

@Python_Dv A

@Python_Dv LEGB variables 15 5

@Python_Dv 15 5 but if we declare "global value" we can see 15 15

@Python_Dv 15 5

@Python_Dv A, since inside the function created value is its own variable disconnected from the variable declared outside of the function.