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@Python_Dv ✅ Option C: [1,3] 😎 a[::2] takes every 2nd element starting from index 0. Watch my slicing cheat sheet : x.com/PyBerryTech/st…

@Python_Dv The correct answer is C) [1, 3]. The Logic: Slicing Syntax In Python (and NumPy), the syntax for slicing an array is [start:stop:step]. In the code, the instruction is a[::2]: Start: (Empty) Defaults to the beginning of the array (index 0). Stop: (Empty) Defaults to the end

@Python_Dv C) [1 3] a = [1, 2, 3, 4] a[::2] means take every 2nd element starting from index 0. Indexes taken → 0 and 2 Values → 1 and 3 Output: [1 3]

@Python_Dv Output: C. a[::2] means “take every 2nd element starting from index 0”, so it picks 1 and 3 (NumPy will print it as [1 3]).

@Python_Dv C. [1,3]

@Python_Dv step is 2 counting will start from 0 . now calculate element 1 and 3

@Python_Dv C

@Python_Dv C) [1, 3]

@Python_Dv B

@Python_Dv C

@Python_Dv C

@Python_Dv [1 3] => it will be without the commas in between 1 and 3 numpy array slicing is same as Python list slicing.

@Python_Dv The output is [1 3]

@Python_Dv C.