Post
@mathssolutionz x²-y² = 2022x - 2022y
(x+y)(x-y) = 2022(x-y)
x+y = 2022
x²+y² = 2024x + 2024y
= 2024(x+y)
= 2024•2022
= (2023+1)(2023-1)
= 2023² - 1²
therefore
√(x²+y²+1) = 2023
Español
@mathssolutionz x²-y² = Nx+y-Ny-x = (N-1)(x-y)
x+y = N-1 if not x=y
? = √(x²+y²+1)
= √(Nx+y+Ny+x+1)
= √((N+1)(x+y)+1)
= √((N+1)(N-1)+1)
= N
Answer:
? = 2023
CY
