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@1drie5

somehow trying to get into tech while having a lot of skill issues

Katılım Mart 2023
210 Takip Edilen114 Takipçiler
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iddu
iddu@1drie5·
it was all my fault
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iddu
iddu@1drie5·
L59 db transactions preserve acid via read/write ops. lifecycle: active → partially committed → committed (or → failed → aborted) concurrency control uses: • locking protocols (e.g., 2pl) • timestamp ordering to ensure serializable execution. #DBMS #SQL #Databases
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iddu@1drie5

L58 minimal cover (canonical cover) eliminates redundant functional dependencies. algorithm: 1. decompose rhs (singleton rule). 2. remove extraneous attributes from lhs determinants. 3. remove redundant fds (if y ∈ x+ without x->y, discard). #DBMS #SQL #Databases

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iddu@1drie5·
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iddu@1drie5·
L58 minimal cover (canonical cover) eliminates redundant functional dependencies. algorithm: 1. decompose rhs (singleton rule). 2. remove extraneous attributes from lhs determinants. 3. remove redundant fds (if y ∈ x+ without x->y, discard). #DBMS #SQL #Databases
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iddu@1drie5

L57 functional dependency sets f and g are equivalent (f ≡ g) iff f+ = g+, meaning f covers g and g covers f. algorithm: 1. for every (x->y) in g, verify y exists in x+ under f. 2. for every (x->y) in f, verify y exists in x+ under g. #DBMS #SQL #Databases

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iddu
iddu@1drie5·
@KidyeYash reached anxiety immunity? atb tho...
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kidye
kidye@KidyeYash·
exam in 2 hours anxiety hasn't kicked in yet am i cooked 🤔
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iddu
iddu@1drie5·
L57 functional dependency sets f and g are equivalent (f ≡ g) iff f+ = g+, meaning f covers g and g covers f. algorithm: 1. for every (x->y) in g, verify y exists in x+ under f. 2. for every (x->y) in f, verify y exists in x+ under g. #DBMS #SQL #Databases
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iddu@1drie5

L56 algorithm to normalize a database relation: 1. find candidate keys. 2. 1nf: atomic values. 3. 2nf: zero partial dependencies. 4. 3nf: for x->y, x is a superkey or y is prime. 5. bcnf: x must be a superkey. decompose on violations. #DBMS #SQL #Databases

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iddu
iddu@1drie5·
L56 algorithm to normalize a database relation: 1. find candidate keys. 2. 1nf: atomic values. 3. 2nf: zero partial dependencies. 4. 3nf: for x->y, x is a superkey or y is prime. 5. bcnf: x must be a superkey. decompose on violations. #DBMS #SQL #Databases
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iddu@1drie5

L55 find the highest normal form sequentially: 1. compute candidate keys. 2. classify prime vs non-prime attributes. 3. evaluate: • 2nf: zero partial dependencies • 3nf: for x->y, x is superkey or y is prime • bcnf: x must be a superkey #DBMS #SQL #Databases

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iddu
iddu@1drie5·
• if your memories were fake, would you still be you? • what truly defines identity? • are we more than programming? • what makes someone “human”? • will something human still survive under total manipulation?
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iddu@1drie5·
L55 find the highest normal form sequentially: 1. compute candidate keys. 2. classify prime vs non-prime attributes. 3. evaluate: • 2nf: zero partial dependencies • 3nf: for x->y, x is superkey or y is prime • bcnf: x must be a superkey #DBMS #SQL #Databases
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L54 5nf (project-join normal form) requires a schema to be in 4nf where every join dependency is implied by candidate keys. it resolves anomalies where a relation must be losslessly decomposed into 3 or more tables, rather than 2. #DBMS #SQL #Databases

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iddu
iddu@1drie5·
தமிழ்நாடு இன்று ஒரு கட்சியை துரோகம் செய்ததல்ல; நல்லாட்சியை சாதாரணமாக எடுத்துக்கொண்டது. அதுவே எந்த சமூகத்தின் மெதுவான சிதைவின் ஆரம்பம்.
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iddu
iddu@1drie5·
L54 5nf (project-join normal form) requires a schema to be in 4nf where every join dependency is implied by candidate keys. it resolves anomalies where a relation must be losslessly decomposed into 3 or more tables, rather than 2. #DBMS #SQL #Databases
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iddu@1drie5

L53 4nf requires a schema to be in bcnf with zero multivalued dependencies (mvds). an mvd (x ->-> y) exists when one attribute determines multiple independent values. grouping them forces cartesian products. fix by decomposing. #DBMS #SQL #Databases

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iddu@1drie5·
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iddu
iddu@1drie5·
L53 4nf requires a schema to be in bcnf with zero multivalued dependencies (mvds). an mvd (x ->-> y) exists when one attribute determines multiple independent values. grouping them forces cartesian products. fix by decomposing. #DBMS #SQL #Databases
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iddu@1drie5

L52 Dependency Preserving Decomposition ensures functional dependencies can be enforced locally in decomposed tables. Rule: (F1 ∪ F2)+ = F+ If verifying an FD requires joins between decomposed tables, it may not be dependency preserving. #DBMS #SQL #Databases

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iddu retweetledi
iddu
iddu@1drie5·
"this is the girl"
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iddu
iddu@1drie5·
I hope he knows that I can see that he suffers, too. And that I want to love him.
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iddu
iddu@1drie5·
L52 Dependency Preserving Decomposition ensures functional dependencies can be enforced locally in decomposed tables. Rule: (F1 ∪ F2)+ = F+ If verifying an FD requires joins between decomposed tables, it may not be dependency preserving. #DBMS #SQL #Databases
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iddu@1drie5

L51 lossless decomposition reconstructs relation r via natural join (r1 ⨝ r2 = r). lossy creates spurious tuples. rule: the intersecting attributes (r1 ∩ r2) must form a candidate or superkey in r1 or r2. #DBMS #SQL #Databases

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kidye
kidye@KidyeYash·
amazing
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iddu
iddu@1drie5·
laugh, and the world laughs with you; weep, and you weep alone
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