Mr Broadwith

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Mr Broadwith

Mr Broadwith

@24HourMaths

Maths is life. #85. #170

Somewhere near Watford Katılım Ekim 2011
400 Takip Edilen2.3K Takipçiler
Mr Broadwith
Mr Broadwith@24HourMaths·
@FO6DC4 Actually, with your wording, maybe I will allow for this one
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Henry D
Henry D@FO6DC4·
@24HourMaths Tried to find a way to minimise the product of the parts, then realised you could basically nullify the middle two and create the smallest possible answer, which in turn happened to be the correct answer. X = -6 (-6 + 3)(-6 + 5)(-6 + 7)(-6 + 9) = -3 * -1 * 1 * 3 = 9
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Matt Becker
Matt Becker@MattBecker82·
@24HourMaths s = t² r = s² = t⁴ AD² = AB² (t – s)² + (s – r)² = 2(s – r)² t – s = s – r t – t² = t² – t⁴ t⁴ – 2t² + t = 0 t(t – 1)(t² + t – 1) = 0 Solve for t in (0,1): t = (√5 – 1)/2 t² = (3 – √5)/2 t⁴ = (7 – 3√5)/2 t² – t⁴ = √5 – 2 AB² = 2(s – r)² = 2(t² – t⁴)² = 18 – 8√5
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Mr Broadwith
Mr Broadwith@24HourMaths·
I'm stuck on this one. Find the area of the circle.
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Henry D
Henry D@FO6DC4·
@24HourMaths Went through it more methodically, found 4 more. 1, 2, 5, 7 1, 3, 4, 5 1, 3, 4, 6 1, 3, 5, 6 I believe this is now every combination
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Mr Broadwith
Mr Broadwith@24HourMaths·
@FO6DC4 I do not think that that is a complete solution set, but your answers are all correct.
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Henry D
Henry D@FO6DC4·
@24HourMaths If I've understood the question correctly, then I think I have 4. 1, 2, 3, 7 1, 2, 4, 5 1, 2, 5, 8 1, 3, 4, 9 I don't believe there are any others
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Mr Broadwith
Mr Broadwith@24HourMaths·
@grundbirn This is correct - there was a typo in the question... the first x shouldn't be there! then it is a smoother answer :)
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Mr Broadwith
Mr Broadwith@24HourMaths·
Back in the game... part 1. For my Y11 this morning.
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Mr Broadwith
Mr Broadwith@24HourMaths·
Part 2... what do we think?
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Mr Broadwith
Mr Broadwith@24HourMaths·
Pete Dyson is at 245 miles and flying (23.7 mph average) - here come the lumps...
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