@Python_Dv Output:73.0
Line 1 = "7" It takes input as a string.
Line 2 = "7"+"0" = "70" then In line it concatenates 7 & 0 as a string .
Line 3 = 70+3 = 73 then in this line the fruits is converted into integer then there is a addition of 70+3.
Line 4 = 73.0 then in this line o/p is infloat
@Python_Dv The Correct answer there is (b)
The loop of Will print '0 1 2' which is less than 3.
Upon exiting the loop, the Else block will print '0'.
Therefore, the output will be '0 1 2 0'