What will happen if we run this program? (it's not fun when you cheat ;)

@EclipseJavaIDE @java People still use eclipse?

@EclipseJavaIDE t1 t2 First of all, check the condition, execute the loop and execute the increment. (Sorry, I answer in spanish before :S)

@EclipseJavaIDE t2 t1

@EclipseJavaIDE t1 t2 Would be infinite loop if i is post incremented.

@EclipseJavaIDE t1 t2

@EclipseJavaIDE @java Invinity loop....

@EclipseJavaIDE I think it will print only t2

@EclipseJavaIDE t2 t1

@EclipseJavaIDE t2 t1

@EclipseJavaIDE I think t1 t2

@EclipseJavaIDE t2 t1

@EclipseJavaIDE @java t1 t2 t1 t2 t1 t2 ...... infinite cause we call function by value hence actual value of i in for loop will not be incremented.

@EclipseJavaIDE @java 300MB of RAM used by the JVM for 2 lines in the console. Thanks you Java.

@EclipseJavaIDE t1 t2

@EclipseJavaIDE @java I didn't see that they are reassigning value so then is t1 t2

@EclipseJavaIDE @java T1t2t1t2

@EclipseJavaIDE @java T1 T2

@EclipseJavaIDE @java t1 t2

@EclipseJavaIDE @java t1 t2 I think.

@EclipseJavaIDE t2 t1

@EclipseJavaIDE @java Print t1 and t2

@EclipseJavaIDE @java t1 t2

@EclipseJavaIDE @java It’s a good note !

@EclipseJavaIDE @java t1 t2

@EclipseJavaIDE @java t1 t2

@EclipseJavaIDE Output : t1 t2

@EclipseJavaIDE @java Stackover flow

@EclipseJavaIDE Should Be t1;t2

@EclipseJavaIDE @java t1 t2

@EclipseJavaIDE @java I will just print a t2

@EclipseJavaIDE @java Increment statement is invoked when loop is over so answer should be: t1 t2

@EclipseJavaIDE I think it prints t1 and t2

@EclipseJavaIDE @java T1 T2

@EclipseJavaIDE @EclipseFdn t1 t2

@EclipseJavaIDE @java This got print t1 and t2 because you send to print these Strings not any variable