I wish there was an easier way to do this 😭

@CodeRed_dev There is. If you rename number variable to n, you can save a lot of time typing all of this 😂

@CodeRed_dev You can, in fact, just do a function for this! So cool! 😀

@CodeRed_dev hold my beer

@CodeRed_dev Real ones remember

@CodeRed_dev I remember showing a classmate the easier trick, for our assignment, and she looked at me like i was a wizard😅

@CodeRed_dev Here it is in Lua. Much shorter: function isEven(n) return not isOdd(n) end function isOdd(n) return not isEven(n) end

@CodeRed_dev If the number leave a remainder when divided( or is an odd number), return false. Otherwise, return true. I could be wrong but, that's the pattern I'm seeing.

@CodeRed_dev Lmao. Looks fancy, but that code though.

@CodeRed_dev Evergreen twitter.com/ctrlshifti/sta…

@CodeRed_dev Mov ax, value Test ax, 1 Jz even Jmp odd

@CodeRed_dev Classic.

@CodeRed_dev Use a modulo to know if the number is odd or not : if (number % 2 == 0) return true; else return false;

@CodeRed_dev I am guessing that is clickbait… definitely getting views 🤣 Anyway. Return (number % 2 ) == 0;

@CodeRed_dev %

@CodeRed_dev def isOdd(x): return True if x % 2 else False def isEven( x ) return False if x % 2 else True

@CodeRed_dev it's called a for loop buddy lol

@CodeRed_dev Just you wait and see what happens if the number is zero 😏

@CodeRed_dev You can use % mod. return Number % 2 == 0;

@CodeRed_dev Maybe vibe coding 🤣

@CodeRed_dev Do “ if(number % 2 == 0) return true; else return false;

@CodeRed_dev am sorry there is none 😭

@CodeRed_dev The fact that people took it seriously 🤣

@CodeRed_dev Bro use a switch.. Duh.

@CodeRed_dev lmao nice click bate!

@CodeRed_dev You can put all the comparisons for even in one if with || and then the else is odd because obviously you've just tested all the evens. It'll probably save you a bit on typing that way

@CodeRed_dev Yandev strikes again!

@CodeRed_dev we have lost the technology. 🤷‍♂️😑

@CodeRed_dev Programming is all about noticing interesting properties, here is how you can make the code much better: return str(number)[-1] in '02468'

@CodeRed_dev the good thing is you only have to do this once for all possible numbers and then export it as an npm package that you can install in every single project of yours

@CodeRed_dev if number %2 == 0, or something like that.

@CodeRed_dev Same. Anyway, gotta get back to my AAA game dev job, the FPS don't crash themselves

@CodeRed_dev I think this gave me psychic damage irl.

@CodeRed_dev Just use a switch

@CodeRed_dev Wait are they related to pirate?

@CodeRed_dev Divisible by 2