What happens if I try to run this program? (only try after committing your answer ;)

@EclipseJavaIDE 1. Variable x1 is initialised (x1= 2) 2. The 1st Static block is executed (x1=3) 3. The 2nd static block is executed (x1 = 1) Final value of x1 = 1

@EclipseJavaIDE Output 1 as x1 = 2, then after x1++ 3, and finally x1 -=2 will make it 1 ( 3-2 )

@EclipseJavaIDE 1, static initializer and block before main()

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@EclipseJavaIDE @java I feel like as a student during the exam times when i read this kind of tweets 😂😂

@EclipseJavaIDE @java 1) static field x1 initialized with 2 2) first static block is executed x1++, so x1 is 3 3) next static block is executed x1-=2, so x1 is 1 4) main-Method is executed so 1 is printed out Seeing multiple static blocks in production code is one of the wtf moments in review.

@EclipseJavaIDE @java I just kill the writer of those lines of code... ^^

@EclipseJavaIDE @java 1

@EclipseJavaIDE @java 1. Variable > block > main

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@EclipseJavaIDE @java Hey you're resetting the values ..lol As I saw suddenly I thought that it must be 3 but still due to the static block this has been initialised earlier and hence it gave 2.....😊😊

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@EclipseJavaIDE @java I'm surprised at the number of people who don't like a puzzle! Career change time?

@EclipseJavaIDE @java 1

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@EclipseJavaIDE @java While class loading the SIB load first from top to bottom, in first static block x1 is having post increment and it will increment x1 by 1 for next usage. In second static block x1 = x1 - 2 is x1 = 3 - 2 become 1 So final value of x1 = 1

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@EclipseJavaIDE @java 1. Initially x1 will be assigned with value 2. 2. First static block will increment value with 1 (x1=3). 3. Second static block will decrement x1 by 2 (x1=1). 4. Main method will print value of x1 as 1.

@EclipseJavaIDE @java 3

@EclipseJavaIDE @java 1

@EclipseJavaIDE Output : 1

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@EclipseJavaIDE Output Is 1

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@EclipseJavaIDE @EclipseFdn 2

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@EclipseJavaIDE Prints 1?

@EclipseJavaIDE @EclipseFdn Variable initiée, Variable ++, Variable -= 2, Print