Does this work? If so, what's the output? (no cheating ;)

@EclipseJavaIDE I suspect its "N", because the result of the addition of the 2 byte values might be broadened to int

@EclipseJavaIDE I think it's B. Byte plus byte should have type byte.

@EclipseJavaIDE Answer is B Explanation: Data type Casting has highest priority Integer 3 and 5 are first converted to datatype Byte before adding them. Therefore the x(Byte i) is called because the argument passed is of Byte data type

@EclipseJavaIDE N

@EclipseJavaIDE The Output Should Be „B“ because I think Byte+Byte Is Byte and does Not count as a Number

@EclipseJavaIDE Operation on bytes results int N

@EclipseJavaIDE I guess it's B. Summing up two bytes will result in a byte.

@EclipseJavaIDE N

@EclipseJavaIDE How about this?

@EclipseJavaIDE N

@EclipseJavaIDE Put instead of Number, it works too public static void x(Serializable n) { System.out.println("n"); }

@EclipseJavaIDE @java B

@EclipseJavaIDE N

@EclipseJavaIDE @java N

@EclipseJavaIDE The arithmetic operations of bytes result in an integer .. and in this case 'int' autoboxed to 'Integer' which is a child of Number .. so x(Number ) is called. and the output is N btw ... one should avoid such overloading of methods

@EclipseJavaIDE Definitely “N”

@EclipseJavaIDE @EclipseFdn N

@EclipseJavaIDE N

@EclipseJavaIDE B. There's no need of byte conversion🤗

@EclipseJavaIDE @java yes, It prints "N". If there is no addition of typecast byte numbers i.e., x((byte)3), then it will print "I".

@EclipseJavaIDE @java Which theme you are using?

@EclipseJavaIDE @java @tafzeelshams 😂😂

@EclipseJavaIDE I think it's b

@EclipseJavaIDE Its 8

@EclipseJavaIDE @java N

@EclipseJavaIDE @java If I remember correctly, you cannot perform mathematical operations on bytes, so they're converted to ints and then summarized. So N. But that could be c#

@EclipseJavaIDE N

@EclipseJavaIDE B?

@EclipseJavaIDE @java B

@EclipseJavaIDE B.