What value of 'i' will be printed out? (don't try it before hand ;)

I meant what value of 's'

@EclipseJavaIDE 2

@EclipseJavaIDE 2

@EclipseJavaIDE It should be 2

@EclipseJavaIDE 2.

@EclipseJavaIDE 2

@EclipseJavaIDE 2

@EclipseJavaIDE s will become 2

@EclipseJavaIDE 2

@EclipseJavaIDE @EclipseFdn 2

@EclipseJavaIDE 2

@EclipseJavaIDE 2

@EclipseJavaIDE 2 (1+ 1 + 0)

@EclipseJavaIDE 2

@EclipseJavaIDE @EclipseFdn 2

@EclipseJavaIDE 2

@EclipseJavaIDE 2?

@EclipseJavaIDE 2

@EclipseJavaIDE 2?

@EclipseJavaIDE 2 (1) + (1) + 0

@EclipseJavaIDE 2

@EclipseJavaIDE My answer is 1.

@EclipseJavaIDE s = 2

@EclipseJavaIDE (1+0) + (0-1) + 0 = 1 -1 + 0 = 0 + 0 = 0

@EclipseJavaIDE 0

@EclipseJavaIDE 1+1+0=2

@EclipseJavaIDE 0

@EclipseJavaIDE It's 0.

@EclipseJavaIDE Evaluation goes left to right (++i) is increment and get so (i=1) is evaluated to 1 + (i--) is get and decrement so is evaluated to 1 and (i=0) + i which is 0 now a final expression is 1+1+0 = 2 S = 2

@EclipseJavaIDE 0

@EclipseJavaIDE My answer is 1 (0+1)+(1-1)+0=1

@EclipseJavaIDE 1

@EclipseJavaIDE It should be 0

@EclipseJavaIDE May be #0

@EclipseJavaIDE 2