Z or X ? (don't cheat there ;)

@EclipseJavaIDE ZZZ 😴 ZZZ

@EclipseJavaIDE Before calling method, char a and z are added and the result, which is integer, is passed. Outcome should be Z

@EclipseJavaIDE If it's not "Z", then come and kill me!!

@EclipseJavaIDE X

@EclipseJavaIDE Z 😉

@EclipseJavaIDE Z

@EclipseJavaIDE X

@EclipseJavaIDE Z?

@EclipseJavaIDE '+' operation would be performed on ASCII values of 'a' and 'z'. It will be 97+122=219. So depending on int 219 function hello(int i) would be invoked and consequently Z printed.

@EclipseJavaIDE Z a+z will always return int value.

@EclipseJavaIDE @sjmaple Z

@EclipseJavaIDE Arithmetic ops involving char, byte, short will be elevated to int so help(int) is called with output 'Z'

@EclipseJavaIDE Z

@EclipseJavaIDE I would say Z

@EclipseJavaIDE Z

@EclipseJavaIDE Z

@EclipseJavaIDE Z

@EclipseJavaIDE @EclipseFdn Zzz

@EclipseJavaIDE Z

@EclipseJavaIDE @sjmaple Z

@EclipseJavaIDE Z

@EclipseJavaIDE X

@EclipseJavaIDE Z

@EclipseJavaIDE Answer: Z, a two primitive char when use arithmetically, the result will be primitive int.

@EclipseJavaIDE Z

@EclipseJavaIDE z

@EclipseJavaIDE I know this but I also wrote a chapter about operator precedence and casting so... I may have cheated 🤣

@EclipseJavaIDE @sjmaple Z

@EclipseJavaIDE Snap. The single quotes are for type Char....

@EclipseJavaIDE @EclipseFdn This will take param as int and prints Z.

@EclipseJavaIDE Z

@EclipseJavaIDE Z

@EclipseJavaIDE Z

@EclipseJavaIDE -hello( char bi) method accepts single parameter of type Char -hello(int i) accepts single param type int hello('a' + 'z') -no single argument is passed to the method -two arguments passed to this method are evaluated as the sum of the ASCII values (int) of chars a & z Ans:Z

@EclipseJavaIDE Hello(219) => print Z