What is the output of this code, and why? Comment your answers below! #python #programming #developer #morioh #programmer #softwaredeveloper #computerscience #webdev #webdeveloper #webdevelopment #pythonprogramming #pythonquiz #ai #ml #machinelearning #datascience

@PythonPr x = x + 3 creates new local integer as ints are immutable. So global x remains 5.

@PythonPr 5 because the parameter x is passed by value, not by reference

@PythonPr No be maths be dis ?😭

@PythonPr Ans. B. 5 x local is changed to 8, but x global remains the same, 5.

@PythonPr The new value is not captured when change (x) is run so it outputs the global 5.

@PythonPr B

@PythonPr 5 Because 3 wasn’t assigned to any parameters

@PythonPr @PythonPr, understanding code execution deeply enhances our problem-solving skills. What insights do you anticipate here? 🤔 #CodingMindset

@PythonPr Output is 5

@PythonPr 8

@PythonPr 8

@PythonPr A

@PythonPr 8

@PythonPr B

@PythonPr B

@PythonPr B

@PythonPr x is 5 cuz the global variable of x is 5 and what is returned to the function beva gets printed otherwise, it would be 8

@PythonPr B. The scoping element ensures that the increment is not applied hence the variable x remains 5

@PythonPr B 5

@PythonPr B

@PythonPr 5 because The function (x) returns a new value (8) but doesn't modify the original variable x because integers are immutable in Python and the function parameter creates a copy. The print(x) statement outputs the original value of x (5).

@PythonPr B. 5

@PythonPr @grok whats the answer

@PythonPr 5

@PythonPr 8

@PythonPr 8