Python Question / Quiz; What is the output of the following Python code, and why? Comment your answers below!

@PythonPr Answer: a) 3|2|1|0| › while(j) means "while j is truthy" › 0 is falsy, all other numbers truthy › j=4: subtract, print 3| › j=3: subtract, print 2| › j=2: subtract, print 1| › j=1: subtract, print 0| › j=0: falsy, loop ends For beginners: while (j) = while j != 0

@PythonPr Answer: (a) 3|2|1|0| The code starts with the variable j initialized to 4. The while loop continues as long as the condition while(j) is true. In Python, any non-zero number is considered True. First iteration: j is 4. The condition while(4) is true. j

@PythonPr Answer: a Explanation👇🏻 The loop starts when j = 4 : while(4) It first decrements j by 1 then prints it and also adds ‘|’ after j It prints 3|2|1| When j = 1 : while(1) It decrements j to 0 and prints 3|2|1|0| j becomes 0 : while(0) Loop terminates.

@PythonPr a. j is decremented by 1 before print statement and loop doesn't execute for j=0.

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@PythonPr a • j is decremented to 3 before the print operation. • The while loop executes until the valuecl of j is >=0, resulting in a string ending in 0|

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@PythonPr A decrement happens after test and before print

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@PythonPr Alternative B: 3|2|1| While loop consider something "True" to run. The number 0 isn't True in bool class, it's False. So, the block doesn't consider the condition valid, and terminates.

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@PythonPr B. 3|2|1|