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Python Programming
Python Programming@PythonPr·
Python Question / Quiz; What is the output of the following Python code, and why? Comment your answers below!
Python Programming tweet media
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Earnest Codes
Earnest Codes@Earnesto037·
@PythonPr Answer: A. [2, 4, 6, 8, 10] In Python, when you assign one variable (like b) to another variable (like a) where the object is a mutable type such as a list, you are making a reference to the same object in memory, not a copy of the object itself. Initially, both variables a and b
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Prime Dev Digital Lab
Prime Dev Digital Lab@ODINAKA_ODINAKA·
@PythonPr A) is correct b[4] = 10 means we are modifying the element at index 4 in list b but a is also modified because b = a makes them point to the same list in memory.
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Coding Computing Coach
Coding Computing Coach@CodingComputing·
@PythonPr Answer: A (yes, the list `a` gets modified!) Solution: Let's see what's happening under the hood. a = [2,4,6,8,9] creates a list with those values, and attaches the name `a` to it. b = a this looks up the list referenced by `a`, and gives it an additional name, `b`. So now +
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Steve
Steve@chistev12·
@PythonPr [2, 4, 6, 8, 10] the list in "a" was assigned to "b", making both variables equivalent. lists are mutable, and using indexing, the last element in the list "9", was replaced with "10"
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Salah
Salah@Salah_Eddine_Gh·
@PythonPr Such quiz are just dead, now Ai can answer them easily unlike before where such quiz provided such fast data to start digging more on mutable variables in python.
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Gonada Inc.
Gonada Inc.@GonadaInc·
@PythonPr The output of the above Python code is: [2, 4, 6, 8, 10] 1. `b = a` creates a new reference to the same list object that `a` points to. Both `a` and `b` now point to the same memory location. 2. `b[4] = 10` changes the original list object that both `a` and `b` reference.
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AI ENGINEER
AI ENGINEER@future_AI_Eng·
@PythonPr I thought B. After watching the comment section , I got to know the answer is B. Would you like to clarify the reason?
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tulip
tulip@tulip19568506·
@PythonPr A because a and b point to same object in memory
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