Python Question / Quiz; What is the output of the following Python code, and why? Comment your answers below!

@PythonPr It prints the character Y, not the value of Y.

@PythonPr None of the options is correct.

@PythonPr The output is: y Because the code is doing updates to the variables X and Y, but the last line is print("y") — that prints the string literal "y", not the value of the variable Y. If it were print(Y), then it would print 8 (since Y = 2 and then Y = Y + 6 → 8).

@PythonPr Output should be small y..from the print("y")

@PythonPr Nine of the above

@PythonPr y

@PythonPr Y

@PythonPr B

@PythonPr 8

@PythonPr E. y

@PythonPr Print (type("y")) <Class string>

@PythonPr B

@PythonPr A

@PythonPr Output: y Because it is given in the quotes and assumed as a string. It will display as a character

@PythonPr Y

@PythonPr B) Y

@PythonPr y

@PythonPr it print y because its ok you are initiallizing 2 variables but you are printing a string "y"

@PythonPr y

@PythonPr One of the above. y ≠ Y

@PythonPr A

@PythonPr print("y") means result "y".

@PythonPr y

@PythonPr None ist correct. It prints y and not Y

@PythonPr first value for y is 2. Then new y is equal first y plus 6. so new value of y is 8. then sintax of print'y' shows 8 on the screen.

@PythonPr 8

@PythonPr The output is: y

@PythonPr None. The y should be printed lowercase.

@PythonPr Answer : B) Explaination: print("Y"), this prints char Y, since it is in double qoute of print function.

@PythonPr A One i want interesting sex girls.

@PythonPr @grok answer

@PythonPr 解なし