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@PythonPr Answer: A) [10, 15, 20, 30]
The code defines a list x with elements [10, 20, 30]. The x.insert(1, 15) method call inserts the value 15 at index 1 in the list, shifting subsequent elements to the right. The list is modified in-place.
Initially, x is [10, 20, 30].
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@PythonPr Answer: A [10, 15, 20, 30]
insert(index, value) adds at that position!
› Original: [10, 20, 30]
› insert(1, 15) puts 15 at index 1
› Shifts everything right
› Result: [10, 15, 20, 30]
For beginners: insert() MODIFIES the list (doesn't return new one). x changes.
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@PythonPr A) [10,15,20,30] why?: list.insert(index, value) insert the value at given index and shifts the existing element right. index starts : 0,1,2... place 15 at postion at 1 so answer will be: [10,15,20,20]
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@PythonPr x.insert(1, 15) inserts the value 15 at index 1, index 1 is before the element 20
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@PythonPr Answer: A — [10, 15, 20, 30]
explanation:
list.insert(i, v) inserts v before index i.
Index 1 is before 20, so 15 goes between 10 and 20.
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@PythonPr A)
insert(index, value) function
in Python is a built-in list method that adds a single element to the list at the specified index position.
- Modifies original list in-place
- Does not return any value
- Shifts elements to insert the value at a particular index
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@PythonPr That should be Error since the .insert works not with list
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@PythonPr A) [10,15,20,30]
Is right ✅️
X.INSERT(1,15) list is mutable so qr can add the elements in existing list.
And insert statement (index,element)
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@PythonPr The code's output depends on the specific code shown, but understanding how the code works helps determine the result.
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@PythonPr A, x is a list which starts from index 0. 15 is inserted in index 1 which is the next position after index 0.
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@PythonPr I'm not an IT guy, but I knew that the built-in function insert took two input the Index and the value, So the list start from index 0, Do it's B.
Am I right?
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