Python Question / Quiz; What is the output of the following Python code, and why? Comment your answers below!

@PythonPr Answer: A) [] The trap: Slicing goes start to stop by step (+1 default) › Start 3 > stop 1 › Step +1 = forward › Can't move forward to earlier index so result is [] For beginners: Use negative step when start > stop. Result is in reverse order! nums[3:1:-1] = [6, 5]

@PythonPr Answer: A → [] In slicing, if the start index is greater than the end index (and no negative step is given), Python returns an empty list. Here nums[3:1] moves forward by default, so nothing is selected.

Answer: A. [] Syntax: list[start:stop] It returns elements from index start up to but not including stop. If start >= stop and no step is specified, the slice returns an empty list. Here: nums[3:1] start = 3, stop = 1 Since 3 > 1, slicing from index 3 to 1 moves forward but stop is behind start. No negative step is specified, so default is +1, which goes forward. Because start is after stop, slice is empty. Summary: Forward slicing with start > stop returns an empty list. x.com/EvyTechno/stat…

@PythonPr Start index = 3 End index = 1 Since 3 > 1 and no negative step is given, Python returns an empty list. Ans---> []

@PythonPr Answer is A) [] nums[3:1] has start > stop with a positive step, so the slice is empty.

@PythonPr I have alot to understand

@PythonPr answer: [] why: list slicing works only when: 1. start > end 2. step is positive

@PythonPr Print [], start at index 3, can't end at index 1 since python can't move backwards.

@PythonPr A ) [] is the right answer. Here we are using concept of list slicing. [Start:end: step_size] , here step size is not mentioned and default step size is 1 so no output will come. It will return empty string.

@PythonPr A. []. since slicing goes forward, nums[3:1] means “start at index 3 and go forward until index 1” → impossible. So the output is []

@PythonPr []

@PythonPr The correct answer isbA. [] ✅ Python list slicing [start:stop] goes from start up to but not including stop. Here, start=3 and stop=1. You cannot go from index 3 to index 1 moving forward, so the result is an empty list [].

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@PythonPr Empty list Bcz List slicing [start:stop]. Here [3:1] here 3 is included but 1 is not thats why result will empty list

@PythonPr [] If the starting index is greater that the "end" index, you get an empty slice

@PythonPr A. [] nums[3:1] means start at index 3, stop at index 1 You can't go backwards with default step. Empty list

@PythonPr None

@PythonPr A) [] ... .@PythonPr

@PythonPr Option A – [] Because start index (3) is greater than end index (1) with a positive step, so it returns an empty list.

@PythonPr A

@PythonPr A. [] We can't move backward in positive indexing

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@PythonPr []