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@Python_Dv Output: hello
Explanation
s = "hello" → s points to "hello"
t = s → t also points to "hello"
s = s.upper() → creates a new string "HELLO" and assigns it to s
t is unchanged because strings are immutable
So print(t) outputs: hello
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@Python_Dv Answer: B) hello
The code works as follows:
Initially, the variable s is assigned the string literal "hello".
A new variable t is created and assigned the value currently held by s. Since strings are immutable in Python, this creates a separate
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The answer to the Python Mind Game in the third image is B) hello.
Here is a step-by-step breakdown of why the output is lowercase, followed by how this core programming concept relates to the data roles you shared:
Why the answer is "hello"
The trick to this "Mind Game" lies in how Python handles variable assignment and string immutability:
s = "hello": A string object "hello" is created in memory, and s points to it.
t = s: Now, the variable t also points to the exact same "hello" object in memory.
s = s.upper(): This is the crucial part. Strings in Python are immutable (cannot be changed). The .upper() method doesn't change the original string; instead, it creates a new string "HELLO". This line reassigns s to the new uppercase version, but t is still pointing to the original lowercase "hello" object.
print(t): Since t was never changed or reassigned, it prints the original value: hello.
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Answer: B (hello)
If you think the key is string immutability, you're wrong. The key is the = operator!
› t = s → both point to "hello"
› s = s.upper() → s REASSIGNED to "HELLO"
› t unchanged (still "hello")
For beginners: s = something creates a NEW binding. Works the same with lists, dicts, any type!
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@Python_Dv B) hello
Strings are immutable in Python.
t = s copies the reference, but s.upper() creates a NEW string. t still points to the original "hello"
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@Python_Dv B) hello: strings in python are immutable can not be changed. s = supper()
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@Python_Dv hello, the last assignment to “t” is hello, so the answer would be option B “hello”
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@Python_Dv B, since string is immutable (unchangeable, unmodifiable), so the changed one becomes another one, while the original keeps unchanged.
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@Python_Dv The value of t is hello and the value string is assigned to t then s.upper()
And print is the value t is hello.
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@Python_Dv B - hello. t still bears the value "hello" since it's a different variable to s though holding similar value
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