Let's take a look at your Java overloading skills. Is it 1? 0? Compile error? Runtime error? (cheaters suck!)

"1 because call get to the most specific match" said @KoreMandar and he's completely right!

@EclipseJavaIDE I believe this code never gets run because it never gets past the code review and merged to trunk. Oh so am I kidding.

@EclipseJavaIDE Compile time error

@EclipseJavaIDE 1 because call get to the most specific match

@EclipseJavaIDE 1, String is a subclass of Object

@EclipseJavaIDE 1

@EclipseJavaIDE @EclipseFdn +++ OUT OF CHEESE ERROR +++

@EclipseJavaIDE Compile error

@EclipseJavaIDE error

@EclipseJavaIDE I think compilation error due to ambiguity

@EclipseJavaIDE Answer is 1. In hierarchy child will get priority. In the absence of String, Object run method will be called

@EclipseJavaIDE 0

@EclipseJavaIDE Error

@EclipseJavaIDE @EclipseFdn Compilation error

@EclipseJavaIDE Compiler error. Must be either run((String)null) or cast with Object

@EclipseJavaIDE Null is not an object, so definitely an error

@EclipseJavaIDE Es gibt den Fehler duplicate method. Eine der beiden methoden darf so nicht definiert werden.

@EclipseJavaIDE 0

@EclipseJavaIDE @EclipseFdn My wish is compile error, but I suspect 0

@EclipseJavaIDE 0

@EclipseJavaIDE Hmmm. Compile error saying it cannot determine which version of “run” to use?

@EclipseJavaIDE 0

@EclipseJavaIDE 0

@EclipseJavaIDE reckon its one of those ambiguous thingy compile errors and needs an explicit cast?

@EclipseJavaIDE Overloading is valid as the argument types are different. Execution of the method run() depends on the order of the static method in the program (class). void run(String s) is executed. Result: 1 Correct/Wrong??

@EclipseJavaIDE Compile error, I had this one in my library. Had to cast null to one of the types.

@EclipseJavaIDE I believe the answer is compile error. Because on the contrary to common belief not everything is an object. Null is not an object. Right?