Python Question / Quiz; What is the output of the following Python code, and why? Comment your answers below!

Answer: B (y). my_list[1] accesses index 1, which is 'y'. For beginners: Python uses ZERO-BASED indexing. Index 0='p', Index 1='y', Index 2='t', etc. my_list[1] gives the SECOND element, not the first!

@PythonPr The way it’s written will out put error, so C is the right answer. If there was indentation B would have been correct.

@PythonPr B. It’s common for a beginner to mistake the first character in a list as the first index. However, lists in Python are 0-indexed, meaning the first character is at index 0, so in this case, index 1 is ‘y’.

@PythonPr B

@PythonPr B.

@PythonPr Identation, Error.

@PythonPr Indentation Error

@PythonPr B.y

@PythonPr B

@PythonPr 😆

@PythonPr With the right indentation-> B) Y But, since print() is not in the right place, C) Error

@PythonPr B

@PythonPr B

@PythonPr @grok what is the answer

@PythonPr B

@PythonPr B

@PythonPr Y, why? Because it’s at index 1

@PythonPr B Python indexing starts at 0.

@PythonPr B.. slicing of list. Uses index 1 ...remember it starts at 0

@PythonPr B

@PythonPr B)y

@PythonPr Y

@PythonPr B

@PythonPr సీ

@PythonPr Y

@PythonPr B.y

@PythonPr B

@PythonPr Error

@PythonPr The answer is B

@PythonPr In Python, list indexing starts from 0. my_list[0] → 'p' my_list[1] → 'y' So the output is y. Correct answer: B (y)

@PythonPr B

@PythonPr y

@PythonPr 😄

@PythonPr B

@PythonPr B