Levi Aggarwal

517 posts

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Levi Aggarwal

Levi Aggarwal

@404xdev

Expert@Codeforces , ICPC Regionalist , Open Source Contributor.

Joined Eylül 2022
136 Following77 Followers
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Levi Aggarwal
Levi Aggarwal@404xdev·
@MahekPatel24 PRACTICE PRACTICE PRACTICE Watching youtube videos/copy pasting your code is not PRACTICE
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Tuki
Tuki@TukiFromKL·
🚨 Do you understand what this man just pulled off.. > a guy from North Carolina used AI to generate hundreds of thousands of songs.. uploaded them to Spotify, Apple Music, Amazon.. then botted billions of streams on his own tracks and walked away with $8 million > 660,000 fake streams per day.. spread across thousands of AI songs so nobody noticed.. $1.2 million a year.. for music no human ever actually listened to real artists are out here grinding for 0.003 cents per stream.. promoting on TikTok.. begging for playlist placements.. and this guy just had AI make the music AND the audience first-ever criminal streaming fraud case.. he's paying back $8 million.. but the playbook is out there now.. and AI just got better since he started the music industry spent 10 years fighting piracy.. now they have to fight songs that don't exist being listened to by people who don't exist.
FearBuck@FearedBuck

The first criminal case of streaming fraud where a North Carolina musician who used AI to make songs, then streamed them billions of times himself making $8 million

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Akash
Akash@kaaaash____·
If a beginner wants to start learning DSA… which playlist would you recommend?
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Levi Aggarwal
Levi Aggarwal@404xdev·
@SumitM_X yarrw , yeh toh sab aata hai . Bas naukri nahi mil pata hai
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SumitM
SumitM@SumitM_X·
As a Backend dev , how many concepts can you explain from below : 1. Event-Driven Architecture 2. Saga Pattern 3. CQRS (Command Query Responsibility Segregation) 4. Event Sourcing 5. Circuit Breaker Pattern 6. Distributed Tracing 7. CAP Theorem 8. Idempotency 9. Data Sharding 10. API Gateway
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Levi Aggarwal
Levi Aggarwal@404xdev·
my iphone phone screen not working 🥲🥲
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Levi Aggarwal retweeted
sunny madra
sunny madra@sundeep·
“If your $500K engineer isn’t burning at least $250K in tokens, something is wrong.”
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VG
VG@HelloVyom·
If you’re buying this shit for 1.8 lakh in 2026 then sorry but you ain’t gonna make it
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Levi Aggarwal
Levi Aggarwal@404xdev·
@Zanies07 @HelloVyom yes , we need to focus our energy on olympiads rather than JEE / NEET. and then we will start seeing good results. Currently all of our students are preparing for only compeitative exams.
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Rightlyso
Rightlyso@Zanies07·
@404xdev @HelloVyom Well most Indians start cp in college and stop it after they get good placements. You can't compete with Chinese where even IMO teams have all LGMs
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VG
VG@HelloVyom·
just 10 contests and man became an International Master 🫡
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divyansh
divyansh@Divyansh91565·
I already started govt job preparation btw
Google AI@GoogleAI

We’re launching a brand new, full-stack vibe coding experience in @GoogleAIStudio, made possible by integrations with the @Antigravity coding agent and @Firebase backends. This unlocks: — Full-stack multiplayer experiences: Create complex, multiplayer apps with fully-featured UIs and backends directly within AI Studio — Connection to real-world services: Build applications that connect to live data sources, databases, or payment processors and the Antigravity agent will securely store your API credentials for you — A smarter agent that works even when you don't: By maintaining a deeper understanding of your project structure and chat history, the agent can execute multi-step code edits from simpler prompts. It also remembers where you left off and completes your tasks while you’re away, so you can seamlessly resume your builds from anywhere — Configuration of database connections and authentication flows: Add Firebase integration to provision Cloud Firestore for databases and Firebase authentication for secure sign-in This demo displays what can be built in the new vibe coding experience in AI Studio. Geoseeker is a full-stack application that manages real-time multiplayer states, compass-based logic, and an external API integration with @GoogleMaps 🕹️

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SumitM
SumitM@SumitM_X·
User changes password. Login with old password still works for a while. Why?
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Rightlyso
Rightlyso@Zanies07·
@HelloVyom @404xdev Avg Indian is like pupil on codeforces bro. If you a specialist you are already massively above avg
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Levi Aggarwal
Levi Aggarwal@404xdev·
@HelloVyom I have not seen any e lafda between these two guys 😭😭. I think its been 3-4 years
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VG
VG@HelloVyom·
what a time, what a time, what a time!!!
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VG
VG@HelloVyom·
Students, which of these companies do you think has an easier interview?
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Shravani
Shravani@shrav_10·
Idk about other gfs, but I will let my boyfriend dress however he wants to, he can also go out with his friends after 6 pm! progressive girlfriend 💅
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divyansh
divyansh@Divyansh91565·
Personal observation on sleep: 7 hours >> 8 hours >> 6 hours >> 3–4 hours >>>>>>>>>> 5 hours 5 hours somehow feels worse than even 3-4 sometimes..
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Moses Koledoye
Moses Koledoye@MoVonLagos·
Reading the replies, I don't think people realize that serving in order of milliseconds at the scale of billions of users requires optimisations at different layers of the OSI model, not merely a fast lookup algorithm which is only a small part of the whole piece.
SumitM@SumitM_X

As a developer, Have you ever wondered : You type a Gmail username and UI instantly shows "Username already taken"... There are millions of users globally How is this check so fast?

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Levi Aggarwal
Levi Aggarwal@404xdev·
@Divyansh91565 I remember solving a problem based on the same concept in icpc chennai regionals last year 🫡🫡
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divyansh
divyansh@Divyansh91565·
So I was solving a graph problem and the core intuition turned out to be just checking whether the graph is bipartite or not (plus a few extra conditions)... So I thought maybe a article kind of , on this.. If you already understand how BFS/DFS works, here's a simple way to check bipartiteness: Bipartite Graph Check - > Most of you already know BFS/DFS. > But many graph problems reduce to a simple question: > Can we divide nodes into 2 groups such that no edge connects nodes of the same group? If yes then graph is bipartite Let's understand the core Idea: Instead of thinking in groups, think in colors: > Assign each node a color (0 or 1) > For every edge -> colors must be different So the problem becomes: Can we 2-color the graph without conflicts? Basic Working: 1. Start from any node: 2. Assign color = 0 3. Their neighbors = 1 4. Continue using BFS/DFS While traversing: If node is unvisited -> assign opposite color If already visited and same color -> NOT bipartite Why This Works? Bipartite => No odd cycle 1) Even cycle -> works fine 2) Odd cycle -> forces same color conflict First-Principles Thinking behind it: This boils down to these points At any node: 1. You only care about previously visited neighbors 2. Constraint: neighbor must have opposite color 3. So each step is just: -> Check conflict -> Assign color -> Continue That's it.
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