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Almost Sure
9.7K posts

Almost Sure
@Almost_Sure
George Lowther, Author of Almost Sure blog, on maths, probability and stochastic calculus. Also on YouTube https://t.co/VyOijwbe9l
London, UK Katılım Eylül 2020
264 Takip Edilen9K Takipçiler

@Almost_Sure @miniapeur Most importantly - he has no notion of metric. My friend and topologist took me with his car to help me get home and left at a distance 3 times the original from it
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@Lptomov82 @miniapeur "well, I can go the standard route, but there's a non-orientable shortcut that I can take. Have you there in half the time."
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@Almost_Sure @miniapeur Never take a taxi, if the driver is a topologist
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@graninas don't worry about kids trophies, go for the Abel prize
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@octonion or maybe I'm confusing the version with the pricing plan and plus is 5.6 sol pro
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The World Cup has no sporting integrity without the confederation which just supplied 75% of its quarter and semi finalists, as well as 5 of its last 6 winners - but more importantly, it ceases to be commercially viable.
FIFA's 'subsidiary' is practically worthless without them.
Martyn Ziegler@martynziegler
BREAKING: UEFA countries unanimously in support of boycotting World Cup in protest at FIFA's plan to sell stakes in tournament to private investors, say sources. Decision taken at emergency virtual meeting thetimes.com/sport/football…
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@TimHenke9 Actually that’s a lot weaker than known zero density results, so it seems reasonable to me now that it follows as a simple consequence of weakly approximating zeta in the strip
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@TimHenke9 But we know that density of zeros is O(logT) so that bounds the maximum you can have in any bounded rectangle. Seems to suggest relative density of zeros more than ε from critical line is 0, but that’s much too strong, must have made a mistake
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@olafwillocx It is. Kind of. Although, in this case, the result mentioned can be proven without such assumptions.
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@Almost_Sure Exactly, this should more often be explained in layman terms. The Riemann conjecture is about the patternless, pseudorandomness of primes.
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@Lptomov82 A lot of time. Not infinite. And the same goes for zeta function universality
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@Almost_Sure The monkey will need an infinite time. And not everything is random. Our work in math includes choices with probability of zero.
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@SeekAllWays Hi @SeekAllWays I’d be interested to see what fable would make of a similar possible counterexample (similar flavor but I made the construction do a bit less at each step). Probably continuing on from the discussion above rather than a fresh session
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@SeekAllWays think you could ask fable that? Supposing the decomposition does exist. So h_∞(x,0) exists and is finite. Does this mean that it has bounded second derivative? Or at least bounded in the measure theoretic sense by some measure? My intuition is that h_n gets smoother
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I know it’s not famous, but would be interested if AI can answer this problem that I laboured over for some time, but gave up on
Almost Sure@Almost_Sure
I’d be very *very* impressed if anyone can answer the following: Can all functions f:R^2->R where f(x,y) is convex in x and increasing in y be written as the difference of functions which are convex in x and *decreasing* in y?
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