Almost Sure

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Almost Sure

Almost Sure

@Almost_Sure

George Lowther, Author of Almost Sure blog, on maths, probability and stochastic calculus. Also on YouTube https://t.co/VyOijwbe9l

London, UK Katılım Eylül 2020
264 Takip Edilen9K Takipçiler
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Almost Sure
Almost Sure@Almost_Sure·
new Youtube video released! An innocent looking meme that's been floating around the internet for a few years, looking like your standard clickbait slop, but actually hides some interesting math using elliptic curves link below
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@Almost_Sure @miniapeur Most importantly - he has no notion of metric. My friend and topologist took me with his car to help me get home and left at a distance 3 times the original from it
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Almost Sure
Almost Sure@Almost_Sure·
@Lptomov82 @miniapeur "well, I can go the standard route, but there's a non-orientable shortcut that I can take. Have you there in half the time."
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Almost Sure
Almost Sure@Almost_Sure·
@graninas don't worry about kids trophies, go for the Abel prize
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Alexander Granin
Alexander Granin@graninas·
I'm 40 tomorrow. I have 1 day left to get a Fields medal. What should I do?
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Almost Sure
Almost Sure@Almost_Sure·
@octonion or maybe I'm confusing the version with the pricing plan and plus is 5.6 sol pro
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Christopher D. Long 🇺🇦🏳️‍🌈🌹
A preemptive statement about unsolved problems being the only sensible problems to solve anecdotally really seems to encourage GPT to work harder on open conjectures.
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Almost Sure
Almost Sure@Almost_Sure·
@dioscuri could stop for a bit of fishing at rutland water
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Henry Shevlin
Henry Shevlin@dioscuri·
Now entering Rutland, smallest county in the UK. Up ahead is the steepest sustained climb of the whole trip. I stopped into the church to say an intercessory prayer to the patron saint of bikes. Also to apply chamois cream.
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Henry Shevlin
Henry Shevlin@dioscuri·
Setting out on my first ever 200km cycle odyssey from Cambridge to Stoke-on-Trent. Should be about 12 hours rather than 10 years, but we’ll see. May document the journey in 30km increments at English places of interest along the way!
Henry Shevlin tweet media
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Alfie | HITC Sevens
Alfie | HITC Sevens@HITCSevens·
The World Cup has no sporting integrity without the confederation which just supplied 75% of its quarter and semi finalists, as well as 5 of its last 6 winners - but more importantly, it ceases to be commercially viable. FIFA's 'subsidiary' is practically worthless without them.
Martyn Ziegler@martynziegler

BREAKING: UEFA countries unanimously in support of boycotting World Cup in protest at FIFA's plan to sell stakes in tournament to private investors, say sources. Decision taken at emergency virtual meeting thetimes.com/sport/football…

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Almost Sure
Almost Sure@Almost_Sure·
@TimHenke9 Actually that’s a lot weaker than known zero density results, so it seems reasonable to me now that it follows as a simple consequence of weakly approximating zeta in the strip
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Almost Sure
Almost Sure@Almost_Sure·
@TimHenke9 But we know that density of zeros is O(logT) so that bounds the maximum you can have in any bounded rectangle. Seems to suggest relative density of zeros more than ε from critical line is 0, but that’s much too strong, must have made a mistake
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Almost Sure
Almost Sure@Almost_Sure·
This is a feature of randomness. Monkey at a typewriter creating the works of Shakespeare and so on
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Almost Sure
Almost Sure@Almost_Sure·
@olafwillocx It is. Kind of. Although, in this case, the result mentioned can be proven without such assumptions.
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Tom Benadryl
Tom Benadryl@olafwillocx·
@Almost_Sure Exactly, this should more often be explained in layman terms. The Riemann conjecture is about the patternless, pseudorandomness of primes.
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Almost Sure
Almost Sure@Almost_Sure·
@Lptomov82 A lot of time. Not infinite. And the same goes for zeta function universality
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@Almost_Sure The monkey will need an infinite time. And not everything is random. Our work in math includes choices with probability of zero.
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Almost Sure
Almost Sure@Almost_Sure·
@SeekAllWays Hi @SeekAllWays I’d be interested to see what fable would make of a similar possible counterexample (similar flavor but I made the construction do a bit less at each step). Probably continuing on from the discussion above rather than a fresh session
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Almost Sure
Almost Sure@Almost_Sure·
@SeekAllWays think you could ask fable that? Supposing the decomposition does exist. So h_∞(x,0) exists and is finite. Does this mean that it has bounded second derivative? Or at least bounded in the measure theoretic sense by some measure? My intuition is that h_n gets smoother
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