MelbMathsJam
164 posts

MelbMathsJam
@MelbMathsJam
MathsJam group in Melbourne meeting at Captain Melville bar on Franklin St.
Melbourne, Victoria Katılım Mart 2017
19 Takip Edilen172 Takipçiler

@carlostph @pickover Not quite. It's only equivalent if there's no bottom on the two-handled cup. Answer is 3.
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Mathematics and mystery.
The debate rages on. "Found this while shopping. How many holes does it have?" tinyurl.com/y97fmj56

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@pickover 3 holes, or genus 3. It's equivalent to the two-handled cup someone posted BUT only if there's a hole in the bottom of the cup too.
Imagine the most obvious hole through the centre was filled in. It still has an extra hole because a loop is formed around that central beam.
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@pickover Although I no longer know anyone's phone number, I do know 10 factorial off the top of my head, and this looks about right.
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@standupmaths Don't forget you have to apply the multiplication tap before the addition tap.
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@MathsJam does anyone have a solution to this puzzle? We only found a degenerate one where one of the triangles flattens to a line.

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Melbourne MathsJam coming up this Tuesday, in person! meetup.com/Melbourne-Math…
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We're going live again! Melbourne MathsJam will be in-person this Tuesday at Captain Melville. meetup.com/Melbourne-Math…
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We also enjoyed this paradoxical quiz question: twitter.com/lancegharavi/s…
Lance Gharavi@lancegharavi
.@jamestanton wtf is going on here
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Tonight we're having fun constructing shapes with ruler and compass, using the website sciencevsmagic.net/geo

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MelbMathsJam retweetledi

Tonight we are discussing slide rules and Napier's bones, plus @RobertCWebb is showing off his models of 4D polytopes. software3d.com/Gallery.php
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Melbourne MathsJam is on tonight at the usual time and place. (7pm @CaptainMelville) See you there for puzzles, games, maths banter and chicken parma!
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@LONMathsJam @MathsJam Ah OK. Yeah we debated just how creative we were allowed to be. The trig answer is perfect, but ceiling etc make it too easy, eg 6 + 6 - 1 - floor(sqrt(sqrt(7)))
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@MelbMathsJam @MathsJam Yes - I think I misremembered that one - what we actually had was:
ceiling((6-1)!/(7+6))
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@MathsJam anyone manage to make 10 from 6, 1, 7, 6 without being TOO creative? And anyone figure out the combining rule puzzle?
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