Python Question / Quiz; What is the output of the following Python code, and why? Comment your answers below!

@PythonPr Answer: (B) Odd The code initializes the variable x with the value 7. The if statement then evaluates the condition x % 2 == 0. The modulo operator (%) returns the remainder of the division. When 7 is divided by 2, the remainder is 1. Since 1 == 0 is False, the code

@PythonPr Answer: B) Odd The pattern: › x % 2 == 0 => Even (divides evenly) › x % 2 == 1 => Odd (has remainder) For x=7: 7 % 2 = 1 (remainder 1) => Odd! For beginners: This is the classic way to check even/odd in programming.

@PythonPr This is checking if the remainder of dividing x by 2 is 0 then it prints even otherwise it will print odd. Since x is set to 7 and 2 goes into 7 3 times with a remainder of 1 it goes to the else block printing odd.

@PythonPr odd because x % 2 gives False so else statement will be executed

@PythonPr Output: B) Odd Because x = 7 and 7 % 2 != 0, the condition fails and the else block runs, printing "Odd".

@PythonPr B) Odd Because 7 % 2 equals 1, not 0, so the else branch runs and prints “Odd”.

@PythonPr anser:odd else block will run here

@PythonPr Odd

@PythonPr B, odd

@PythonPr B

@PythonPr Odd

@PythonPr B) Odd. 7 % 2 is 1, so I hit the else. No trick here.

@PythonPr Odd

@PythonPr Option B :

The correct answer is B) Odd.

@PythonPr Odd

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@PythonPr D

@PythonPr B . Odd

@PythonPr Odd

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@PythonPr B) Odd

@PythonPr B) odd

@PythonPr B

@PythonPr B) Odd

@PythonPr odd

@PythonPr option B.

@PythonPr B

@PythonPr B) Odd is the correct answer. Here the value x =7 value assgined then we use simple if and else statements, x%2== 0 reminder opertaor so value is 7 means else condition is triggered output will be odd.

@PythonPr B) Odd

@PythonPr Odd

@PythonPr B) Odd ... @PythonPr

@PythonPr B

@PythonPr Lots of people saying odd. Somehow I think its even but I'm not a programmer 🤷‍♂️

@PythonPr B